How do you alphabetically sort a string in java (without arrays)?

System.out.println(“Enter any phrase that you like rearranged.”);
userInput = calculator.nextLine();
System.out.println();
System.out.println(userInput);

with regard to (char page = ‘a’; page < 'z'; letter++)

//This is usually all We have so a long way, I don’t know how to print the actual letters alphabetically.

TRIAL INPUT #1
THE PRICE OF BREAD IS USUALLY $1.25 PER POUND
TRIAL OUTPUT #1

THE PRICE OF BREAD IS USUALLY $1.25 PER POUND
ABCDDEEEEFHIINOOPPPRRRSTU

If you change your own Q&As to help public you’ll get more aid from my home.

Here’s a way that does what you would like:

static Stringed rearrange(String str)
Stringed outStr = “”;
with regard to (char page = ‘a’; page < 'z'; letter++)
with regard to (int nited kingdom = 0; nited kingdom < str.length(); k++)
in the event (str.charAt(k) == letter)
outStr += str.charAt(k);
System.out.printf(
“%c”, str.charAt(k));

System.out.println();
returning outStr;

final results:

Enter your phrase that you like rearranged.
The price of bread is usually $1.25 per single lb.

The price of bread is usually $1.25 per single lb.
abcddeeeefhiinooppprrrsu

I imprinted and returned the worthiness because the way that we was tests it.

use that ascii table
or get some way to convert these char in order to int.
as well as word involving note,
intended for (char letter = ‘a’; notice < 'z'; letter++)
that will line isn’t going to work
cause
‘a’+1 does not make feel.