Exact value for csc105?

i’ve this problem to operate on for my trig exam are you able to help me

csc105
= 1/sin105

Most of us know sin105 = (6 + 2)/4
=> 1/(6 + 2)/4
= 4/(6 + 2)
= 4(6 — 2) / (6 + 2)(6 :2)
= 4(6 — 2) / (6 :2)
= 4(6 — 2) / 4
= SIX – A COUPLE OF.